9b^2+10=910

Solution for 9b^2+10=910 equation:

9b^2+10=910

We move all terms to the left:

9b^2+10-(910)=0

We add all the numbers together, and all the variables

9b^2-900=0

a = 9; b = 0; c = -900;
Δ = b2-4ac
Δ = 02-4·9·(-900)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*9}=\frac{-180}{18}
=-10
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*9}=\frac{180}{18}
=10
$